X^2+0,5x-1,5=0

Solution for X^2+0,5x-1,5=0 equation:

X^2+0.5X-1.5=0

a = 1; b = 0.5; c = -1.5;
Δ = b2-4ac
Δ = 0.52-4·1·(-1.5)
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{6.25}}{2*1}=\frac{-0.5-\sqrt{6.25}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{6.25}}{2*1}=\frac{-0.5+\sqrt{6.25}}{2}
$